c - Why this program with execl breaks if not run with sudo? -

this diner_info program:

#include <stdio.h>  #include <stdlib.h>  int main(int argc, char *argv[]) {     printf("diners: %s\n", argv[1]);      printf("juice: %s\n", getenv("juice"));      return 0; } 

and compiled file called diner_info

and here program:

#include <stdlib.h> #include <stdio.h> #include <unistd.h>  int main(int argc, char *argv[]){     char *my_env[] = {"juice=peach , apple", null};     execle("diner_info", "diner_info", "4", null, my_env); } 

when run program this:

korays-mbp:hello2 koraytugay$ sudo ./a.out  diners: 4 

no problem...

but when do not include sudo getting segmentation fault. why?

operating system os x.

it shouldn't, , made mistake first binary. tested on mac , on ubuntu 14.04 box, , both base runs fine:

brenohl@sid:/tmp$ ./a.out  diners: 4 juice: peach , apple  brenohl@sid:/tmp$ cat diner.c  #include <stdlib.h> #include <stdio.h> #include <unistd.h>  int main(int argc, char *argv[]){     char *my_env[] = {"juice=peach , apple", null};     execle("diner_info", "diner_info", "4", null, my_env); }  brenohl@sid:/tmp$ cat diner_info.c  #include <stdio.h>  #include <stdlib.h>  int main(int argc, char *argv[]) {     printf("diners: %s\n", argv[1]);      printf("juice: %s\n", getenv("juice"));      return 0; }