java - How to escape a invalid string using regular expression? -

i have below string, being escaped incorrectly.

 "\"name\":\"\"/test/name=testame\" 001\"" 

i use regular expression find strings contain above pattern , replace correct escape pattern. @ moment, i'm using hard coding find , replace string, not want.

ps: i've no control of above string pattern. i'll have handle incorrectness in application.

any suggestions?

this help:

• \\ finds \
• \" finds "
• [a-za-z_-]+ enough match labels , names
• [0-9]+ match number without screwing or finding much
• : , = literals , don't need escaping

put 'em , you've got night regular expression.

i don't see in question prohibit doing substitution using parenthesis, didn't tool you're using replacing can't give many hints. you'll put

(part 1 of regexp)some literal hate(part 2 of regexp)  

as matcher ,

\1some literal like\2 

as substitution string. if going perl you'd use

s\matcher\substituter\g. 

you perl one-liner, you'd have double careful in re-escaping quotes.