Find the Standard Deviation from a CSV File using Python -

i have csv file named 'salaries.csv' content of files follows:

city,job,salary delhi,doctors,500 delhi,lawyers,400 delhi,plumbers,100 london,doctors,800 london,lawyers,700 london,plumbers,300 tokyo,doctors,900 tokyo,lawyers,800 tokyo,plumbers,400 lawyers,doctors,300 lawyers,lawyers,400 lawyers,plumbers,500 hong kong,doctors,1800 hong kong,lawyers,1100 hong kong,plumbers,1000 moscow,doctors,300 moscow,lawyers,200 moscow,plumbers,100 berlin,doctors,800 berlin,plumbers,900 paris,doctors,900 paris,lawyers,800 paris,plumbers,500 paris,dog catchers,400 

i need print standard deviation of salaries of each profession.
older version of python. cannot use statistics , numpy.

from __future__ import with_statement import math import csv open("salaries.csv") f:   def average(f): return sum(f) * 1.0 / len(f) variance = map(lambda x: (x - avg)**2, f) standard_deviation = math.sqrt(average(variance)) print standard_deviation 

can me, newbie field of python.

error : typeerror('argument 2 map() must support iteration',) 

the output should

plumbers 311 lawyers 286 doctors 448

to details per profession, create dictionary instead:

from __future__ import with_statement import math  def get_stats(profession, salaries):      n = float(len(salaries))   mean = sum(salaries)/n   stdev = 0   value in salaries:     stdev += (value - mean)**2   stdev = math.sqrt(stdev/(n))   print profession, min(salaries), max(salaries), mean, stdev  open('salaries.csv') f:   f.readline()   # create list of salaries    salaries = {}    line in f.readlines():     country, profession, value = line.split(',')     value = int(value.strip())     profession = profession.strip()     if salaries.has_key(profession):         salaries[profession].append(value)     else:         salaries[profession] = [value]   k,v in salaries.items():     get_stats(k,v)