digital logic - How to find period of the clock pulse with frequency. -


for example: period 10ms , need find frequency this: f= 1/t = 1/10ms = 100hz because (10ms=.01 seconds, 1/.01=100)

i understand when changes larger unit such ghz confused.

example: if frequency of clock pulse 2ghz, period of clock pulse?

my thoughts: f= 2ghz= 2 000 000 000hz
t= 1/f = 1/2 000 000 000?? somehow doubt close answer. explain 1 me? million.

the period correct calculated it.

p = 1/f p = 1/2ghz = 1/(2×10^9) p = 0.0000000005s (second) p = 0.0000005ms (millisecond) p = 0.0005us (microsecond) p = 0.5ns (nanosecond) p = 500ps (picosecond)

another way @ 2ghz 2×10^7 times faster 100hz period should 2×10^7 times shorter

2ghz/100hz = 2×10^7 10ms/(2×10^7) = 500ps

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