c - Building error leads the Code Blocks to quit -

i'm writing c code solve numerical problem, define 100x100 matrix , fill values matrix, b solution : a[i][j]=1/(i+j+1) , b[i]= sum of values in ith row following code:

#include <stdio.h> #include <stdlib.h> #define n 100 int main() {     double a[n][n];     double b[n];     int i,j;     (i=0;i<n;i++)         (j=0;j<n;j++)         {             b[i]=0;             a[i][j]=0;         }     (i=0;i<n;i++)         (j=0;j<n;j++)         {             a[i][j]=1/(i+j+1);             b[i]+=a[i][j];         }      int c=10;      (i=0;i<n;i++)         (j=0;j<n;j++)         {              printf("%lf\t",a[i][j]);              if (c==j) printf("\n");              c=c*10;         }       return 0; } 

whenever click on build button code blocks terminates, shows :

cross platform ide stopped working

and program closes. can me figure out problem?!

you have problem a set 0, juste use 1. use double instead of int

#include <stdio.h>                                                              #include <stdlib.h>                                                             #define n 100                                                                   int main()                                                                      {                                                                                   double a[n][n];                                                                 double b[n];                                                                    int i, j;                                                                       (i = 0; < n; i++)                                                             (j = 0; j < n; j++)                                                         {                                                                                   b[i] = 0;                                                                       a[i][j] = 0;                                                                }                                                                           (i = 0 ; < n; i++)                                                            (j = 0; j < n; j++)                                                         {                                                                                   a[i][j] = 1. / (i + j + 1);                                                     b[i] += a[i][j];                                                            }                                                                            int c = 10;                                                                      (i = 0; < n; i++)                                                             (j = 0; j < n; j++)                                                         {                                                                                   printf("%lf\t", a[i][j]);                                                       if (c == j) printf("\n");                                                       c *= 10;                                                                    }                                                                             return 0;                                                                   }