Python - if statements involving numpy arrays -

i'm opening image , converting array of rgba values. here's code:

img = image.open('17112013.png') imgarray = array(img) l = imgarray[:,1,1] m = imgarray[1,:,1] n = imgarray[1,1,:] bluecount = 0 redcount = 0 flag = 0  in range(0,len(l)):     j in range(0,len(m)):         if (imgarray[i,j] == [255,255,255,255]):             pass         if (imgarray[i,j] == [0,0,0,255] , flag == 0):             pass         if (imgarray[i,j] == [255,0,0,255] , flag == 0):             pass         if (imgarray[i,j] == [0,0,255,255]):             flag = 1             bluecount = bluecount + 1         if (imgarray[i,j] == [255,0,0,255] , flag == 1):             redcount = redcount + 1         if (imgarray[i,j] == [0,0,0,255] , flag == 1):             flag = 0         if (imgarray[i,j] == [255,255,255,255] , flag == 1):             flag = 0 

if run such, receive following:

valueerror: truth value of array more 1 element ambiguous. use a.any() or a.all() 

i understand need use these 'if' statements containing numpy arrays; however, unsure of correct syntax implement this. being stupid, appreciated.

you want like:

if np.all(imgarray[i,j] == [255,255,255,255]): 

if particular slice of imgarray indeed [255,255,255,255], equality comparison return array([ true, true, true, true], dtype=bool). can't expect if know boolean array directly, have discovered, function numpy.all(x) returns true if of values in array x equivalent true , false otherwise.