PHP search array and return only first value that meets criteria -

i have directory of files labeled yyyy-mm-dd.jpg.

using php, trying search through array of these files , print filename (without jpg) of latest date before today.

for example: today 2015-04-14

files:

• 2015-04-20.jpg <-in future
• 2015-04-11.jpg <-first file has date before today's date
• 2015-04-02.jpg
• 2015-04-01.jpg

i want return "2015-04-11".

i've been working on couple days, trying piece things multiple posts. so, i've gone through lot of iterations. here one:

$scan = scandir($comic_path,1); //go through directory desc $last_comic = substr($scan[0],0,10); //substr scan date  function lastcomic(){     foreach ($scan $acomic) {   if ($acomic < $last_comic) {     echo $acomic . "\n";   }   $last_comic = $acomic; }} lastcomic($last_comic); 

thanks in advance help.

well, code in way:

$today = date("y-m-d"); $last_comic = substr($scan[0],0,10); foreach ($scan $acomic) {     $only_date = substr($acomic,0,10);     if ($only_date < $today) {         $last_comic = $acomic;         break;     } } 

is you're trying accomplish?